177k views
2 votes
given a triangle with sides measuring 18 inches,21 inches 14 inches find the measure of the anglewith the greatest ​

1 Answer

4 votes

ANSWER


A = 80.98 \degree

Step-by-step explanation

The angle with the greatest measure corresponds to the longest:

Since we know the three side lengths, we use the cosine rule to obtain;


{a}^(2) = {b}^(2) + {c}^(2) - 2bc \cos(A)

where a=21, b=18 and c=14


{21}^(2) = {18}^(2) + {14}^(2) - 2 * 18 * 14\cos(A)


44 1= 324+ 196 - 504\cos(A)


44 1= 520 - 504\cos(A)


44 1 - 520 = - 504\cos(A)


- 79 = - 504\cos(A)


\cos(A) = 0.1567


A = \cos ^( - 1) (0.1567) = 80.98 \degree

correct to the nearest hundredth.

User Ericjbasti
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories