Question

Find the surface area of the regular hexagonal pyramid. Round your answer to the nearest hundredth

Answer 1

Answer:A i guess i am soooooooooo sorry if i am wrong

Explanation:

Answer 2

(B)
`SA=79.18m^2`

Explanation:

It is given from the figure, the side of the regular hexagonal pyramid is 3 m, slant height is 6.2 m and height is 5.6 m.

The formula for Surface area of the regular hexagonal pyramid is:

`SA=(pl)/(2)+B`

where B is the area of the base, p is the perimeter and l is the slant height.

Now, the perimeter can be found as:

`P=6{*}3`

`P=18 m`

And, the area of the base is:

`B=(3√(3)s^2)/(2)`

Substituting the value of s in the above formula, we get

`B=(3√(3)(3)^2)/(2)`

`B=23.382m^2`

Now, substituting the values of B, and P in the formula of Surface area, we get

`SA=\frac{18{*}6.2}{2}+23.382`

`SA=79.18m^2`

Thus, the Surface area of the regular hexagonal pyramid is
`79.18m^2`.

Hence, option B is correct.