Question

a certain spring has a spring constant of 1962 n/m.if its period of vibration is 1.419 s, what is its mass?

Answer 1

100.2 kg

Step-by-step explanation:

The period of vibration of a spring-mass system is given by

`T=2\pi \sqrt{(m)/(k)}`

where

T is the period

m is the mass

k is the spring constant

In this problem, we know

T = 1.419 s is the period

k = 1962 N/m is the spring constant

Re-arranging the equation, we can find the mass:

`m=k((T)/(2\pi))^2=(1962 N/m)((1.419 s)/(2\pi))^2=100.2 kg`