What is the value of the positive zero of the function , f, defined by f(x) =x^2-121

Question

asked Sep 22, 2020 199k views

2 Answers

Drzax · Answer 1 · 2020-09-24T11:00:29+0000

Answer: 11

Explanation:

You need to substitute
f(x)=0 into the function given:

$f(x) =x^2-121\\0 =x^2-121$

Now you need to solve for the variable "x", to do this, first you must add 121 to both sides of the function:

$(121)+0=x^2-121+(121)\\121=x^2$

Now apply square root to both sides of the function. Then, you get:

$\±√(121)=\±√(x^2)\\\\\±√(121)=x\\\\x_1=11\\x_1=-11$

The value of the positive zero of the function is 11.

Morten Fjeldstad · Answer 2 · 2020-09-25T19:41:51+0000

Answer:

The positive zero is 11

Explanation:

Given in the question an equation,

f(x) =x² - 121

We are asked to find the positive zero of f(x)

means x > 0 for which f(x) = 0

so,

x² = 121

Take square root on both sides of the equation

√x² = √121

x = ±11

which means that x = 11 and x = -11

Since x > 0 so we will reject x =-11 and we will accept x = 11