Answer:
The number could be
or
![x=-1/3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zi9raswcp1xjwbeernkptw4jo4esp6tzv6.png)
Explanation:
Let
x-----> the number
Remember that
The reciprocal of a number is 1 divided by the number
we know that
![x+2((1)/(x))=-(19)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gpe6nuux8r0cir7zg9ag42jjlm9mre6v5i.png)
Solve for x
Multiply by 3x both sides
![3x^(2) +6=-19x\\ \\ 3x^(2)+19x+6=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/deaadnjq6weqzblbl53p8qn1j5o6rii6vc.png)
Solve the quadratic equation by graphing
The solutions are
![x=-6, x=-1/3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wlfwne67q4r9gsi0o38t7e41ifirtpae8f.png)
see the attached figure
Verify both solutions
For
![x=-6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vonkhrwgbx30e802kvl9sbsobo4wso692s.png)
![-6+2(-(1)/(6))=-(19)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/krqmrvklem2v7iqpvigv7apitp1qc60mhk.png)
----> is true
For
![x=-1/3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zi9raswcp1xjwbeernkptw4jo4esp6tzv6.png)
![-(1/3)+2((1)/((-1/3)))=-(19)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9ucqw9pjjv1dipougisveiiv1h97avcdlw.png)
----> is true