Question

Figure GHTA below is a parallelogram. = 6 cm, = 8 cm, and the measure of = 60°. Find the area.

Answer 1

The answer would be D 48V3 cm ^2

the v is the root btw

Answer 2

The area of parallelogram GHTA is
`41.568 cm^2`.

Explanation:

Given parallelogram GHTA

GH = 8 cm =-AT

GA = 6 cm

∠ GAT =∠ GHT = 60°

To find = Area of parallelogram

Solution:

Draw perpendicular GO on the base AT.

In ΔGOA

`\sin 60^o=(GO)/(GA)=(GO)/(6 cm)`

(sin 60°=0.8660)

GO = 5.196 cm

Area of the parallelogram: GO × AT

`=5.196 cm* 8 cm =41.568 cm^2`

The area of parallelogram GHTA is
`41.568 cm^2`.