Answer:
The area of parallelogram GHTA is
.
Explanation:
Given parallelogram GHTA
GH = 8 cm =-AT
GA = 6 cm
∠ GAT =∠ GHT = 60°
To find = Area of parallelogram
Solution:
Draw perpendicular GO on the base AT.
In ΔGOA
(sin 60°=0.8660)
GO = 5.196 cm
Area of the parallelogram: GO × AT

The area of parallelogram GHTA is
.