Question

Ken has a toy chest with hot wheels cars. He has 6 camaros, 2 Lamborghinis, 4 corvettes, 8 Ferraris and 12 mustangs. Ken wants to keep his little brother occupied while he does his homework. Ken reaches into the toy chest without looking and gets a car to give to his little brother. What is the probability that Ken will choose a Lamborghini or Corvette from his toy chest? Express your probability answer as a fraction, decimal and percent.

help plissss

Answer 1

Lamborghini=
fraction = 2/32
Decimal = 0.0625
Percentage= 6.25%

Corvette=
Fraction= 4/32
Decimal=0.125
Percentage=12.5%



Step-by-step explanation:


Since the problem says “lamborghini OR corvette” you need to add the probability amount of both cars together. There are 2 lamborghinis and 4 corvettes, so 2+4=6. Now, put this number over the total amount of all cars. 6+2+4+8+12=32. So, the probability will be 6/32 which simplifies to 3/16. In decimal form this is .1875, and in percent form this is 18.75% (move the decimal 2 places to the right)