Question

In quadrilateral ABCD, the sides BC and AD are congruent. The diagonal AC is the bisector of the angle BAD=160 degrees, thats is 8 times greater than angle ACB. Find the measure of angle ADC

pls help

Answer 1

Answer:
`50^(\circ)`

Explanation:

`m\angle CAB=m\angle CAD=80^(\circ)` (angle bisector)

`m\angle ACB=20^(\circ)` (one-eighth of
`\angle BAD`)

`m\angle ABC=80^(\circ)` (sum of angles in a triangle)

`\overline{AC} \cong \overline{BC}` (converse of base angles theorem)

`m\angle ADC=50^(\circ)` (base angles theorem)