Answer:
the solution is the last one.
Explanation:
We know that for a second grade equation of the type:
ax^2 + bx + c = 0
The solution will be given by the quadratic formula, which states that:
x1 = [-b + sqrt(b^2 - 4ac)]/2a
x2 = [-b - sqrt(b^2 - 4ac)]/2a
So, according to the solution, we have:
x1 = [-5 + 2sqrt(7)]/3
Then:
2a = 3
-b = 5
b^2 - 4ac = 28
Solving each equation:
a = 2/3
b= -5
c = 9/8
None of the alternatives equals the values obtained before. So we can say that the expression is simplified.
Now we knoe what the first and second equation are wrong because b is not equal to -5.
So we have the other two alternatives, where b=-10. This gives us an idea that maybe, the equation is simplified by two. If that's the case:
then:
2a = 6
b= -10
b^2 - 4ac = 112
Then b=-10, a = 3 and c=-1
So the solution is the last one.