Question

To what volume should 5.0 g of KCl be diluted in order to prepare a 0.25 M solution?​

Answer 1

0.268 L

Step-by-step explanation:

concentration is the number of moles of solute in 1 L of solution

number of moles of KCl - 5.0 g / 74.5 g/mol = 0.067 mol

the concentration of the solution to be prepared - 0.25 mol/L

concentration = number of moles of KCl / volume of solution

substituting the values in the equation

0.25 mol/L = 0.067 mol / V

V = 0.268 L

solution should be diluted to 268 mL to make a 0.25 M solution