Question

What are the amplitude, period, and phase shift of the given function?

Answer 1

The correct choice is B.

Explanation:

The given function is

`f(t)=-(1)/(3)\sin (4t-3\pi)`

The given function is of the form;

`y=A\sin(Bt-C)`

where

`|A|=|-(1)/(3)| =(1)/(3)` is the amplitude.

The period is calculated using the formula;

`T=(2\pi)/(|B|)=(2\pi)/(|4|)=(\pi)/(2)`

The phase shift is given by;

`(C)/(B)=(-3\pi)/(4)`

The correct choice is B