What are the amplitude, period, and phase shift of the given function?

Question

asked Sep 19, 2020 114k views

1 Answer

Ruslash · Answer 1 · 2020-09-25T16:26:14+0000

Answer:

The correct choice is B.

Explanation:

The given function is

$f(t)=-(1)/(3)\sin (4t-3\pi)$

The given function is of the form;

$y=A\sin(Bt-C)$

where

|A|=|-(1)/(3)| =(1)/(3) is the amplitude.

The period is calculated using the formula;

$T=(2\pi)/(|B|)=(2\pi)/(|4|)=(\pi)/(2)$

The phase shift is given by;

$(C)/(B)=(-3\pi)/(4)$

The correct choice is B