Question

Which equation could generate the curve in the graph below?

Answer 1

the answer is c

hope this would help you

Answer 2

`y=-2x^2 -16x -28`

Explanation:

We are given with the graph of a parabola

`y=-2x^2 + 3x -5`

a=-2, b=3 and c=-5

Discriminant =
`b^2-4ac= 3^2 -4(-2)(-5)= 9-40= -31`

Discriminant is negative so x intercepts are imaginary.

In the graph we have two x intercepts.

`y=-2x^2 -4x -2`

a=-2, b=-4 and c=-2

Discriminant =
`b^2-4ac= (-4)^2 -4(-2)(-2)=0`

Discriminant is 0 so there is only one x intercept

`y=-2x^2 -16x -28`

a=-2, b=-16 and c=-28

Discriminant =
`b^2-4ac= (-16)^2 -4(-2)(-28)=32`

Discriminant is positive so there are two x intercepts

`x=(-b+-√(b^2-4ac) )/(2a) =(16+-√(32) )/(2(-2))`

We will get two values for x

x= -5.414 , x=-2.586

Two x intercepts are negative . That is the x intercepts of given graph.

`y=-2x^2 +16x -28`

a=-2, b=16 and c=-28

Discriminant =
`b^2-4ac= (16)^2 -4(-2)(-28)=32`

Discriminant is positive so there are two x intercepts