Question

a two digit number has three times as many tens than ones. The difference between the number and twice the reversed number is 15.Find the number

Answer 1

The answer is 93
3x3=9
93-39-39=15

Answer 2

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Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,x=3y⋯(i)

Reversed number = 10y + x

A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)

⇒9x−9y=36

⇒x−y=4⋯(ii)

⇒3y−y=4

∴2y=4 x=3y ∴x=6

y=2

∴ Number = 62