Question

Find the Sin A, Cos A, and Tan A. (Write your answer as simplified ratios.)

Answer 1

see explanation

Explanation:

sinA =
`(opposite)/(hypotenuse)` =
`(BC)/(AB)`, thus

sinA =
`(2√(19) )/(20)` =
`(√(19) )/(10)`

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cosA =
`(adjacent)/(hypotenuse)` =
`(AC)/(AB)`, thus

cosA =
`(18)/(20)` =
`(9)/(10)`

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tanA =
`(opposite)/(adjacent)` =
`(BC)/(AC)`, thus

tanA =
`(2√(19) )/(18)` =
`(√(19) )/(9)`