Question

A seagull can fly 25 meters downward in 2 seconds. To find the average velocity of the seagull.what equation will you use?

Answer 1

`v=(d)/(t)`

Step-by-step explanation:

The average velocity of a moving object is given by:

`v=(d)/(t)`

where

d is the displacement of the object

t is the time taken

In this problem, we have

d = 25 m is the displacement

t = 2 s is the time

Therefore, the average velocity of the seagull is

`v=(25 m)/(2 s)=12.5 m/s`

Note that velocity is a vector, so it has not only a magnitude, but also a direction, which corresponds to the direction of the displacement (downward, in this example).