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What is the difference r+2/r+4-3/r+1

User Stickley
by
7.5k points

2 Answers

7 votes

Answer:


(r^2-10)/((r+4)(r+1))

Explanation:

We want to evaluate:


(r+2)/(r+4)-(3)/(r+1)

We collect the least common multiple of the denominators to get:


((r+2)(r+1)-3(r+4))/((r+4)(r+1))

Expand the numerator:


(r^2+3r+2-3r-12)/((r+4)(r+1))


(r^2-3r+3r+2-12)/((r+4)(r+1))


(r^2-10)/((r+4)(r+1))

User Darshil Jani
by
7.8k points
5 votes

Answer:


( r^2-10)/((r+4)(r+1))

Explanation:


(r+2)/(r+4) - (3)/(r+1)

To simplify the fractions we take common denominator

LCD is (r+4)(r+1)

we try to get same denominator on both fraction

multiply the first fraction by r+1 and second fraction by r+4


((r+2)(r+1))/((r+4)(r+1)) - (3(r+4))/((r+1)(r+4))

(r+2)(r+1) becomes r^2 +3r+2

3(r+4) becomes 3r+12


( r^2 +3r+2)/((r+4)(r+1)) - (3r+12))/((r+1)(r+4))


( r^2 +3r+2-3r-12)/((r+4)(r+1))

combine like terms


( r^2-10)/((r+4)(r+1))

User Desimusxvii
by
7.7k points

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