Question

What is the value of the discriminant for the quadratic equation -3=-x^2+2x? discriminant =b^2-4ac

Answer 1

D = 16

Explanation:

`-x^2+2x=-3\qquad\text{add 3 to both sides}\\\\-x^2+2x+3=0\\\\a=-1,\ b=2,\ c=3\\\\\text{Substitute to}\ D=b^2-4ac:\\\\D=2^2-4(-1)(3)=4+12=16`

Answer 2

Discriminant = 16

Explanation:

We have the following expression: -3 = -x^2 + 2x

Organizing the expression, we have: x^2 - 2x -3 = 0

We know that for an equation of the type: ax^2 + bx + c = 0, the discriminant is: b^2-4ac

From our equation we know that a=1, b=-2, and c=-3.

Then Discriminant = (-2)^2 - 4(1)(-3)

Discriminant = 4 +12 = 16