Question

What is the equilibrium expression for
2SO3(g) 0₂(g) +2SO₂(g)

Answer 1

`K_(c) =([O_(2) ] [SO_(2) ]^(2) )/([SO_(3) ]^(2) )`

Step-by-step explanation:

To construct the equilibrium constant, you need the balanced equation:

2 SO₃(g) -----> O₂(g) + 2 SO₂(g)

The equilibrium constant compares the concentrations of the products and the reactants.

The given expression follows this structure:

aA(g) ----> bB(g) + cC(g)

In this equation, the uppercase letters symbolize the molecules and the lowercase letters symbolize their corresponding coefficients in the balanced equation.

The general equilibrium expression looks like this:

`K_(c) =([B]^(b) [C]^(c) )/([A]^(a) )`

To be clear, the concentrations in the numerator represent the gaseous products and the concentrations in the denominator represent the gaseous reactants.

Therefore, the equilibrium expression for this equation is:

`K_(c) =([O_(2) ] [SO_(2) ]^(2) )/([SO_(3) ]^(2) )`