Question

Simplify completely.

Answer 1

`\large\boxed{√(27y^8)=3y^4\sqrt3}`

Explanation:

`√(27y^8)=\sqrt{9\cdot3\cdot y^(4\cdot2)}\\\\\text{Use}\ √(ab)=√(a)\cdot√(b),\ (a^n)^m=a^(nm)\ \text{and}\ √(a^2)=a\\\\=\sqrt9\cdot\sqrt3\cdot√((y^4)^2)=3\cdot\sqrt3\cdot y^4=3y^4\sqrt3`