Question

Equation of the circle with center 2,1 and 5,2 a point on the circle

Answer 1

Answer: (x-2)^2+(y-1)^2=10

Explanation:

r=√(x-h)^2+(y-k)^2

r=√(5-2)^2+(2-1)^2

r=√3^2+1^2

r=√9+1

r=√10

X^2+y^2=r^2

(x-2)^2+(y-1)^2=(√10)^2

(x-2)^2+(y-1)^2=10

Answer 2

Explanation:

The center tells you how to handle the left side of a circle's equation.

(x - 2)^2 + (x - 1)^2 = r^2

The point (5,2) gives you enough information to find r^2

x = 5

y = 2

(5 - 2)^2 + (2 - 1)^2 = r^2

(3)^2 + 1^2 = r^2

9 + 1 = r^2

r^2 = 10

Complete equation

(x - 2)^2 + (y - 1)^2 = 10