Answer:
The surface area is
![404.8\ in^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/htqe7d3vhttyysnduo2dyw1pfavl358iuk.png)
Explanation:
we know that
The surface area of the figure is equal to
![SA=2B+PL](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6gudw6m8t4qhsr0dxamk3klgaijxkrb583.png)
where
B is the area of the trapezoidal face
P is the perimeter of the trapezoidal face
L is the length of the figure
Find the area of B
![B=(1)/(2)(15+5)8\\ \\B=80\ in^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/aftqy0afmw15f6wvh8ympx871z7u6j59jj.png)
Find the perimeter P
![P=(8+5+12.8+15)=40.8\ in](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vsclyp4v4cgxqqu5pzzvia27ov993jdrh0.png)
we have
![L=6\ in](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b16jdhoexr2sl6o5o0zup4vlb9nyl96skf.png)
substitute the values
![SA=2(80)+(40.8)(6)=404.8\ in^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kbvg7a3askdmfagfuyzhd8w0ynzubtl0bi.png)