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If M = N, the diameter of M = 148, and AB = 140, what is the length of NQ?

If M = N, the diameter of M = 148, and AB = 140, what is the length of NQ?-example-1

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Answer:


NQ=24\ units

Explanation:

we know that

Triangles ABM and CDN are congruent

so

CD=AB

AB=2AL ----> because the diameter divide the circle into two equal parts

CQ=AL=140/2=70 units

NC----> is the radius

NC=148/2=74 units ----> the radius is half the diameter

Applying Pythagoras Theorem find the value of NQ


NC^(2)=NQ^(2)+CQ^(2)

substitute the values


74^(2)=NQ^(2)+70^(2)


NQ^(2)=74^(2)-70^(2)


NQ^(2)=576


NQ=24\ units

User Symeon Quimby
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