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Line AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to ?

A.
5x − 3y = 0
B.
-x + 3y = 0
C.
-5x − 3y = 0
D.
3x + 5y = 0
E.
-3x + 5y = 0

2 Answers

5 votes

Answer:

c is the correct answer

Explanation:

User Suraj Bahl
by
7.7k points
7 votes

Answer:

3y+5x=0

Explanation:

The question is on equations of parallel lines

Finding the gradient m of line AB

m=change in y coordinates/change in x-co-ordinates

Given points A(-3,0) and B (-6,5)

m=Δy/Δx Δy=5-0=5 Δx=-6 - -3= -3 ⇒m= - 5/3

Equation

The line will have its gradient equal to - 5/3

m=-5/3

point is the origin (0,0)

m=Δy/Δx

y-0/x-0 = -5/3

3(y-0)=-5(x-0)

3y-0= -5x+0

3y=-5x

3y+5x=0

User Kaushik Shankar
by
8.9k points

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