Question

a horizontal force of 2500 N is applied for a time of 30 seconds to the car mass of 1000 kg if the car is at rest and friction is negligible determine the distance travelled by the car​

Answer 1

Newton’s second law: F=ma. 2500=1000a. a=2.5m/s*s. Final velocity is 2.5*30=75m/s. Average speed is (Vi+Vf)/2, which is 37.5m/s. D=vt. 37.5*30=1125m. The distance traveled is 1125 meters