Question

Which equation yields the solutions x=−3 and x=−4?

a)2x2+14x+24=0
b)x2−6x+5=0
c)3x2+30x+48=0
d)−3x2−12x+15=0

Answer 1

a) 2x² + 14x + 24 = 0

Explanation:

a)

2x² + 14x + 24 = 0

2(x + 4) (x + 3) = 0

x = -4 or x = -3

b)

x² - 6x + 5 = 0

(x - 1)(x - 5) = 0

x = 1 or x = 5

c)

3x² + 30x + 48 = 0

3 (x + 8) (x + 2) = 0

x = -8 or x = -2

d)

-3x² - 12x + 15 = 0

-3 (x + 5) (x - 1) = 0

x = -5 or x = 1