Question

In the figure AB is parallel to CD. BC is parallel to AE. angle ABD measures (3x+4). angle BCD measures (6x-8). angle EDF measures (7x-20). what is the degree measure of angle BCD?

Guys I really need ur help. my test is tomorrow and I've been stuck on this question since yesterday. I literally am about to have a mental breakdown
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Answer 1

Explanation:

great job!

Answer 2

The measure of angle BCD is
`68.5\°`

Explanation:

step 1

Find the value of x

we know that

`m<ABD+m<BCD+m<EDF=180\°` -----> form a straight line

substitute the values

`(3x+4)\°+(6x-8)\°+(7x-20)\°=180\°`

`(16x-24)\°=180\°`

`16x=180\°+24\°`

`16x=204\°`

`x=12.75\°`

step 2

Find the measure of angle BCD

`m<BCD=(6x-8)`

substitute the value of x

`m<BCD=6(12.75)-8=68.5\°`