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Suppose a mother carries two recessive genes for freckles (rr) and a father carries one recessive gene for freckles and one dominant gene for clear facial skin (Rr). What is the likelihood that their first child will have freckles?
A)
1
2
B)
1
4
C)
3
4
D)
4
4

User Rossana
by
5.6k points

2 Answers

4 votes

Answer:

1/2 or 50%

Step-by-step explanation:

-3-

User Jason McVetta
by
6.2k points
5 votes

r r

R Rr Rr

r rr rr

Genotype of the mother with freckle trait is rr. This means that it is a recessive trait.

Genotype of of the father having clear facial skin is Rr, showing that it is a dominant trait. There can be two genotypes for this trait that is Rr and RR.

When these parents are crossed, they produce 50% offsprings with the freckles trait (rr) and 50% with clear facial skin ( Rr).

Therefore, the likelihood of the first child with freckles is A

Hope this helped , Danielle xo

User Amit K Bist
by
5.9k points