Question

Balance this reaction Al4C + H2O = Al(OH)+ CH4

Answer 1

Answer:Al4C + 4(H20) = 4AL(OH) +CH4

Step-by-step explanation:

the equation is balance on both sides,

4 aluminums on both sides

1 carbon on both sides

8 hydrogens on both sides

4 oxygens on both sides

Answer 2

Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄

Step-by-step explanation:

The correct formulas are

Al₄C₃ + H₂O ⟶ Al(OH)₃ + CH₄

Often, the best way to start is to balance all atoms other than O and H, then balance O, then balance H.

1. Put a 1 in front of the most complicated-looking formula (Al₄C₃):

1Al₄C₃ + H₂O ⟶ Al(OH)₃ + CH₄

2. Balance Al:

We have fixed 4 Al on the left. We need 4 Al on the right. Put a 4 in front of Al(OH)₃.

1Al₄C₃ + H₂O ⟶ 4Al(OH)₃ + CH₄

3. Balance C:

We have fixed 3 C on the left. We need 3 C on the right. Put a 3 in front of CH₄.

1Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄

4. Balance O:

We have fixed 12 O on the right. We need 12 O on the left. Put a 12 in front of H₂O.

1Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄

Every formula now has a fixed coefficient. The equation should be balanced.

5. Check that atoms balance:

\
`\begin{array}{ccc}\textbf{Atom} & \textbf{On the left} & \textbf{On the right}\\\text{Al} & 4 & 4\\\text{C} & 3 & 4\\\text{H} & 24 & 24\\\text{O} & 12 & 12\\\end{array}`

The balanced equation is

Al₄C₃ + 12H₂O ⟶ 4Al(OH)₃ + 3CH₄