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What the answer I can’t find it

What the answer I can’t find it-example-1
User CSM
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1 Answer

1 vote

Answer:

1. 6 students

2. 20 students

Explanation:

To find how many students the instructor must have to make a profit set f(x) = 0 and then solve for n. If it comes out as a decimal round up to the nearest whole number. If it comes out s a whole number add one. This is because 0 is not considered a profit it is considered breaking even. Also you can't have a fraction of a person. Also it is easier to solve for zero than for .01 which is the smallest profit you can make. Anyways...

0 = 70n - 400

0 + 400 = 70n - 400 + 400

400 = 70n

400/70 = 70n.70

5.7 = n

So, to make a profit the instructor needs to have 6 students.

To solve for how many students the instructor needs to have to make $1,000 per month, make f(x) = 1,000

1,000 = 70n - 400

1000 + 400 = 70n - 400 + 400

1400 = 70n

1400/70 = 70n/70

20 = n

The instructor needs to have 20 students to make a $1,000 profit.

User Riegardt Steyn
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7.2k points