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How much heat is absorbed by 34g iron skillet its temperature rises from 12c to 24 c ?

1 Answer

3 votes

Answer:


1.84\cdot 10^5 J

Step-by-step explanation:

The heat absorbed by the piece of iron is given by:


Q=mC_S \Delta T

where:

m = 34 g is the mass of the piece of iron


C_s = 450 J/g^(\circ)C is the specific heat of iron


\Delta T=24 C-12 C=12^(\circ)C is the variation of temperature of the piece of iron

Substituting numbers into the formula, we find


Q=(34 g)(450 J/gC)(12 C)=1.84\cdot 10^5 J

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