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A gas occupies 318 liters at 10.0 atm. What is the pressure if the volume becomes 662.5 L?

User Shahriyar
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1 Answer

5 votes

Answer:

4.8 atm.

Step-by-step explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and T are constant, and have two different values of V and P:

P₁V₁ = P₂V₂

P₁ = 10.0 atm, V₁ = 318.0 L.

P₂ = ??? atm, V₂ = 662.5 L.

∴ P₂ = P₁V₁/V₂ = (10.0 atm)(318.0 L)/(662.5 L) = 4.8 atm.

User Michael Socha
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