Answer:
1 → D
2 → A
3 → B
4 → C
Explanation:
You need to remember that:
![cos\alpha=(adjacent)/(hypotenuse)\\\\sin\alpha=(opposite)/(hypotenuse)\\\\tan\alpha=(opposite)/(adjacent)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sn3qjhatfbs62jq7qy92lsb91v68l6mrwu.png)
Then:
-For angle B, you can identify in the figure that:
![opposite=b\\adjacent=c\\hypotenuse=a](https://img.qammunity.org/2020/formulas/mathematics/middle-school/57g6htulj6wvbyl1hvfl3f8ocl415002l4.png)
Then, you can substitute values and get:
![cosB=(c)/(a)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rvwse0otidfv8imxdwjddvioik2p0qqih6.png)
![sinB=(b)/(a)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iaiv1l3j9bfzb104h07vkfkz2un35hnqcl.png)
![tanB=(b)/(c)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h74gdqexfnhwywl1185bmbbpjsh2hubpe2.png)
- For angle C, you can identify in the figure that:
![opposite=c\\adjacent=b](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4xt82npc7feij06miekhdmbcr095bh7g22.png)
Therefore, substituting values, you get that:
![tanC=(c)/(b)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b3po3kpfngxhowr7xbb6ps307i6hllg0gd.png)