Hello!
The answer is:
The equation of the new line will be:
![y=-0.5x+6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a5fsa9mk1m77pgwd9lotxsv422swbcizo6.png)
or
![y=-(1)/(2)x+6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ez3zcan7bw9evuouq6d6k6yxedjamh859k.png)
Why?
To solve the problem, we need to remember the slope intercept form of a line.
The slope intercept form of a line is given by the following equation:
![y=mx+b](https://img.qammunity.org/2020/formulas/mathematics/high-school/8nudzfk4b5l0arb9iixag2w8am6zn99zlr.png)
Where,
y, is the function.
x, is the variable of the function.
m, is the pendant of the line.
b, is the y-axis intercept of the line.
So, we are given the line that will be parallel to the line that we are looking for:
![2x+4y=10\\4y=-2x+10\\4y=-2(x-5)\\y=(-2)/(4)*(x-5)\\\\y=-(1)/(2)*(x-5)\\\\y=-(1)/(2)x+(5)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wkm89kdne6o1jqdybfsnbuaibjif6vhkg0.png)
Where,
![m=-(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/949vzv7fnr3yt14uoxkzqanql7dj8l30nf.png)
Then,
We need to use the same slope to guarantee that the new line will be parallalel to the given line-
So, our new line will have the following form:
![y=-(1)/(2)x+b](https://img.qammunity.org/2020/formulas/mathematics/middle-school/etok3plpexdeoca0jeh1hyehvh860hu3c0.png)
We need to substitute the given point to isolate "b" in order to guarantee that the line will pass through.
Now, substituting the given point, to calculate"b", we have:
Calculating b, we have:
![2=-(1)/(2)8+b](https://img.qammunity.org/2020/formulas/mathematics/middle-school/smvydtaowoze5wry36y8nnv33pv3hvggr4.png)
![2=-4+b](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3nlsuqnrukz8gi3tctjw16sig4lb38jtt4.png)
![2+4=b](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wsesjav0epvo8iyu7bp0tifafngccu1olu.png)
![6=b](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lk0mz3iuk1i4lgf5c8bkelf6q8fexqnt4e.png)
Hence, we have that the equation of the new line will be:
![y=-0.5x+6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a5fsa9mk1m77pgwd9lotxsv422swbcizo6.png)
or
![y=-(1)/(2)x+6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ez3zcan7bw9evuouq6d6k6yxedjamh859k.png)
Proving that the line will pass through the given point, by substituting it into its equation, we have:
![2=-0.5(8)+6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y517nh1x8arxi44jnbh2c6u8echjab5x8k.png)
![2=-4+6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sfz93tz8qqad9sro4oj6ef681djiv9op5h.png)
![2=2](https://img.qammunity.org/2020/formulas/mathematics/high-school/7noj6vr77unrt5xf7nfqnsip03i9kd5i2j.png)
So, since the equality is satisfied, we know that the line pass through the new line.
Have a nice day!