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A train approaching a crossing changes speed from 10 m/s to 25 m/s in 240 s. How can the train's acceleration be described?

User Enselic
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1 Answer

3 votes

Answer:


\boxed{\text{The train is speeding up by 0.0625 m/s every second}}

Step-by-step explanation:

Acceleration (a) is the change in velocity (Δv) divided by the change in time (Δt).


a = (\Delta v)/(\Delta t) = (v_(2) - v_(1) )/(t_(2) - t_(1)) \\\\a = (25 - 10)/(240 - 0)=(15 )/(240)=\text{0.0625 m/s}^(2)\\\\\ \boxed{\textbf{The train is speeding up by 0.0625 m/s every second}}\\

User Beyowulf
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