Question

Factor 9abc + 3ac + 12bc completely. A) 3abc(3ab + a + 4b) B) 3c(3ab + a + 4b) C) 3(3ab + a + 4b) D) c(3ab + a + 4b)

Answer 1

B) 3c(3ab+a+4ab)

Explanation:

First find the common factor of (9abc+3ac+12bc) (the common factor is 3c because 3 is the greatest common factor of the coeffecients given and c is in all the terms of the variables given)

then, put 3c outside the parenthesis and factor the terms.

3c(3ab+a+4ab)

when you multiply 3c(3ab+a+4ab) you should get the polynomial that the question gave you. (9abc+3ac+12bc)

Answer 2

the answer Is B) 3c(3ab+a+4b)