Question

Solve by completing the square x^2+12x+32=0​

Answer 1

x = - 8, x = - 4

Explanation:

Given

x² + 12x + 32 = 0 ( subtract 32 from both sides )

x² + 12x = - 32

To complete the square

add (half the coefficient of the x- term)² to both sides

x² + 2(6)x + 6² = - 32 + 6²

(x + 6)² = - 32 + 36 = 4

Take the square root of both sides

x + 6 = ± 2 ( subtract 6 from both sides )

x = - 6 ± 2

Hence

x = - 6 - 2 = - 8

x = - 6 + 2 = - 4

Answer 2

hello : x = - 4 or x = - 8

Explanation:

x²+12x+32=0​

(x² +2(6)(x) +6²) - 6² +32 = 0....by completing the square

(x + 6 )²- 2² = 0

(x+6-2)(x+6+2)=0 by idetity : a² - b² = (a - b ) ( a + b )

(x+4)(x+8) =0

x+4=0 or x+8= 0

x = - 4 or x = - 8