Answer:
The time at which the ball will reach its maximum height is t= 3 seconds.
Explanation:
To find the the time at which the ball will reach its maximum height, we need to solve the model given - 3x2 + 18x +7
since h(t) is the height given we can re-write the equation as:
h(t)= -3(t)² + 18t +7
Differentiating the above equation
![(dt)/(dh) = -6t + 18](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sm1cg43w9gy14c5p50e7f8csjsi5qv1ulz.png)
When the ball is at maximum height
![(dt)/(dh)=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sexqwdujg3dxdu87yz7ngi1awwruink0b7.png)
0=-6t+18
-18 = -6t
=> t= -18/-6
=> t= 3
the time at which the ball will reach its maximum height is t= 3 seconds.
We can find the maximum height by putting value of t in equation:
h(3) = -3(3)²+ 18(3) +7
h(3)= -27 + 54 + 7
h(3)= 34 ft