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A solution contains 100 mg/mL of a drug, and the recommended dose is 50 mg/lb. once a day. How much solution would be needed for one dose to be administered to a 20 kg patient?

A. 2.2 L
B. 220 mL
C. 22 L
D. 22 mL

2 Answers

3 votes

Answer:20 kg * 2.2 lb/kg * 50 mg/lb * 1mL/100mg = 22 mL

Step-by-step explanation:

User Rajeev Atmakuri
by
6.9k points
0 votes

Answer:

The correct answer is option (D) 22mL

Step-by-step explanation:

Solution:

Given:

liquid concentration = 100mg/mL

weight = 20kg

dosage = 50mg/lb

converting the dosage from mg/lb to mg/kg, we have

1kg = 2.2046lb

therefore, dosage = 50mg * 2.2046/kg = 110.23mg/kg

The required solution can be obtained using the formula below

Dose = weight in kg * dosage in mg/kg ---------------1

liquid dose = dose/liquid concentration----------------2

Substituting into equation 1, we have

Dose = 20kg * 110.23mg/kg = 2204.6mg

For liquid dose, substitute into equation 2

Liquid dose = 2204.6mg/100mg/mL

22. 046mL

Approximately 22mL

Therefore, 22mL is needed to be administered to the 20kg patient

User BFree
by
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