Question

Find the total electric charge of 1.7 kg of electrons. me=9.11×10−31kg, e=1.60×10−19C.

Answer 1

`2.99\cdot 10^(11)C`

Step-by-step explanation:

The mass of one electron is

`m_e = 9.11\cdot 10^(-31)kg`

So the number of electrons contained in M=1.7 kg of mass is

`N=(M)/(m_e)=(1.7 kg)/(9.11\cdot 10^(-31)kg)=1.87\cdot 10^(30)`

The charge of one electron is

`e=1.60\cdot 10^(-19) C`

So, the total charge of these electrons is equal to the charge of one electron times the number of electrons:

`Q=Ne=(1.87\cdot 10^(30))(1.6\cdot 10^(-19)C)=2.99\cdot 10^(11)C`