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Rewrite the following logarithm. log⁡xy
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Rewrite the following logarithm.
log⁡xy

User Monad
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Explanation:


\text{Use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log(xy)=\log(x)+\log(y)\\\\\text{Where}\ x>0\ \text{and}\ y>0.

User Fitch
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