Question

Verify the equation below with each of the values listed for z to find a solution . 3-2z=1/10

Answer 1

`</p><p>3-2z=(1)/(10) \\</p><p>30-20z=1\\</p><p>-20z=-29 \\</p><p>z=(-29)/(-20) \Longrightarrow z=\boxed{1.45}</p><p>`

Answer 2

For this case we have the following equation:

`3-2z = \frac {1} {10}`

We must find the value of z that represents the solution of the equation:

We follow the steps below:

We multiply by 10 on both sides of the equation:

`10 (3-2z) = 1`

We apply distributive property to the terms of parentheses;

`30-20z = 1`

We subtract 30 from both sides of the equation:

`-20z = 1-30\\-20z = -29`

We divide between -20 on both sides of the equation:

`z = \frac {-29} {- 20}\\z = \frac {29} {20}\\z = 1.45`

If we substitute the value of z in the original equation, equality is satisfied.

Answer:

`z = 1.45`