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The slop-intercept form of the equation of a line that passes through points (-2,-13) is y=5x-3 what is the point slope form of the equation of the equation for this line

The slop-intercept form of the equation of a line that passes through points (-2,-13) is-example-1
User Donut
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2 Answers

1 vote

Answer:

y + 13 = 5(x + 2)

Explanation:

y=5x-3 what is the point slope form of this equation?

The point-slope form looks like y - k = m(x - h), where (h, k) is the given point and m is the given slope.

Here the given point is (-2, -13). Therefore, the desired equation is:

y -(-13) = 5( x - [-2] ), or

y + 13 = 5(x + 2)

User Tom Shaw
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7.2k points
0 votes

Answer:


y+13=5(x+2)

Explanation:

The given function passes through (-2,-13).

The slope-intercept form of this equation is
y=5x-3.

This implies that; the slope of the given function is;


m=5

The point-slope form of this function is given by the formula;


y-y_1=m(x-x_1)

We have
(x_1,y_1)=(-2,-13)

We substitute the point and the slope into the function to obtain;


y--13=5(x--2)


y+13=5(x+2)

User David Roe
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