130k views
5 votes
The equation v(x)=32500(0.92)^x how much more is the truck worth after two years than after three years

1 Answer

5 votes

Answer:

the difference: $2,192.64

Explanation:

After 1 year, the truck has lost 8% of its value: v(x) = $32,500(0.92)^1, or

$29,900.

After 2 years, v(x) = $32,500(0.92)^2, or $27,500. Finally, after 3 years,

v(x) = $32,500(0.92)^3 = $25,307.36.

Subtracting $25,307.36 (the value after 3 years) from $27,500 (the value after 2 years) yields the difference: $2,192.64

User Majid Adibian
by
5.5k points