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Zn + 2 HCl --> ZnCl2 + H2 How many moles of hydrochloric acid (HCl) are used (assume a complete reaction) if 8.3 moles of zinc chloride (ZnCl) are produced? A 8.3 mol ZnCl2 B None of these answers C 8.3 mol HCl D 4.15 mol HCl E 16.6 mol HCl

1 Answer

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Answer:

E. 16.6 mol HCl

Step-by-step explanation:

The equation for the reaction is;

Zn + 2 HCl --> ZnCl2 + H2

From the reaction 2 moles of HCl produces 1 mole of ZnCl2

Therefore; 8.3 moles of ZnCl2 will be produced by;

= 8.3 moles ×2

= 16.6 Moles of HCl

Therefore; E. 16.6 mol HCl

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