Question

two charged objects are a certain distance apart. what happens to the force between them if one charge is tripled?​

Answer 1

The force is tripled too.

Step-by-step explanation:

The magnitude of the electric force (repulsion or attraction) between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance that separates them (Coulomb's Law).

`F=k_(e) ([q_(1)][q_(2)])/(r^(2))`

Where

`k_(e)` is the Coulomb's constante.

`q_(1)` and
`q_(2)` are the signed magnitude of the charges.

`r` the distance between charges.

So, if one of the charge is tripled, due the directly proportional product of the charges, the force will be tripled.

`F=k_(e) ([3q_(1)][q_(2)])/(r^(2))`

or

`F=k_(e) ([q_(1)][3q_(2)])/(r^(2))`

The result will be still the force tripled.