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10 votes
10 votes
Use special right triangles to find the value of the variables no decimal answers

Use special right triangles to find the value of the variables no decimal answers-example-1
User Mantu Nigam
by
2.7k points

2 Answers

14 votes
14 votes

Answer:

Below in bold.

Explanation:

The first triangle is a 30-60-90 triangle,

so the sides are in the ratio 2 : 1 : √3, where 2 is the hypotenuse, the 1 is adjacent to 60 degree angle and the √3 is opposite the 60 degree angle.

So x = 1/2 * 32 = 16

and y = 16√3 or 27.71 to nearest hundredth.

The second one is the same special triangle, so

√3/2 = 12/b

b = 24/√3

= 8√3 or 13.86 to nearest hundredth.

a = 1/2 b = 4√3 or 6.93 to nearest hundredth.

User Cristianoms
by
2.8k points
30 votes
30 votes

Explanation:

This is trigonometry. Focusing on Y initially, we can see that Y is the opposite, and 32 is the hypotenuse. Therefore, we must use sin:


\sin(60) = (y)/(32)


y = \sin(60) * 32


y \approx28

Next X. We can see that X is the adjacent, and 32 is the hypotenuse, so we must use cos:


\cos(60) = (x)/(32)


x = \cos(60) * 32


x = 16

Now let's look at A. We can see that a is the adjacent, and 12 is the opposite, so we must use tan:


\tan(60) = (12)/(a)


a = (12)/( \tan(60) )


a \approx7

Now, B. We can see that B is the hypotenuse, and 12 is the opposite, so we must use sin:


\sin(60) = (12)/(b)


b = (12)/( \sin(60) )


b \approx14

User Ybull
by
3.1k points
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