Question

Need help !!!!! ASAP

Answer 1

Hello!

The answer is:

The new volume is 2.84 L.

`V_(2)=2.84L`

Why?

To solve the problem, we need to remember what STP means. STP means that the gas is at standard temperature and pressure, or 273.15 K (0°C) and 1 atm.

Also, we need to use the Combined Gas Law, since the temperature, the pressure and the volume are being changed.

The Combined Gas Law establishes a relationship between the temperature, the pressure and the volume of an ideal gas using , Gay-Lussac's Law, Charles's Law, and Boyle's Law.

The law is defined by the following equation:

`\frac{P_(1)V{1}}{T_(1)}=\frac{P_(2)V{2}}{T_(2)}`

Where,

`P_(1)` is the first pressure.

`V_(1)` is the first volume.

`T_(1)` is the first temperature.

`P_(2)` is the second pressure.

`V_(2)` is the second volume.

`T_(2)` is the second temperature.

So, we are given the following information:

`V_(1)=2L\\P_(1)=1atm\\T_(1)=0\°C=273.15K\\P_(2)=80kPa=0.8atm\\T_(2)=37\°C=37+273=310K`

Then, isolating the new volume, and substituting, we have:

`\frac{P_(1)V{1}}{T_(1)}=\frac{P_(2)V{2}}{T_(2)}\\\\V_(2)=\frac{P_(1)V{1}}{T_(1)}*(T_(2))/(P_(2))\\\\V_(2)=(1atm*2L)/(273.15K)*(310K)/(0.8kPa)=2.84L`

Hence, the new volume is 2.84 L.

`V_(2)=2.84L`

Have a nice day!