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A geometric sequence {an} is defined by the function

f(1) = a1 = 6 and f(n) = an = (1.2)*f(n - 1) for n ≥ 2.

Find f(38).
A)273.6


B)326.26
C)5103.3735
D) 6124.0482
User Janmenjaya
by
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1 Answer

1 vote

ANSWER

C)5103.3735

Step-by-step explanation

The recursive definition of the given sequence is;


f(1) = a_1 = 6

and


f(n) = a_n = (1.2) * f(n - 1)

The explicit definition is


f(n) = a_n =6 (1.2)^(n - 1)

We substitute n=38 to obtain:


f(38) = a_ {38}= 6(1.2)^(37)


f(38) = 5103.3735

The correct choice is C.

User AlreadyLost
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