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Solve for x in the equation ? 2x^2 +3 x-7 =x^2 +5x +39

Solve for x in the equation ? 2x^2 +3 x-7 =x^2 +5x +39-example-1

1 Answer

1 vote

Answer:

1 ± √47

Explanation:

Combine like terms in 2x^2 +3 x-7 =x^2 +5x +39:

2x^2 - x^2 = x^2 (first term);

3x - 5x = -2x (second term);

-7 - 39 = -46 (third term)

Then we have, all on the left side, x^2 - 2x - 46, which is a quadratic equation. Here the coefficients are a = 1, b = -2 and c = -46.

Then the discriminant, b^2 - 4ac, is:

(-2)^2 - 4(1)(-46) = 4 + 184.

The roots are:

-(-2) ±√188 2 ± √4√47

------------------- = -------------------

2 2

= 1 ± √47 (last of the answer choices)

=

x = ------------------

User Swapnil Kadam
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